(62lineatus erit angulus dAC=BRS. III.Tansfer mensulam ex R in in S, & si-mul perticâ metire intervallum Rs, quodsecundùm proportionem scalae (238)transferes in rectam AC ex A in O(nempe quot perricarum &c. estRS,tot partes decimas &c. transferes ex Ain O.) IV. Mensulam in S sic statue,ut regulâ rectae AC applicatâ punctumR per dioptras appareat: quo facto, utanteà puncto A, sic nunc puncto O, ap-plicabis regulam, & per dioptras colli-mans in punctum B duces rectam Od:haec secabit in d rectam Ad in prima sta-tione ductam. Jam V. rectam Ad cir-cino interceptam scalae applica, & vide(238) quot ea complectatur partes deci-mas, centesimas, millesimas: totidemenim perticas, pedes decimales, pollicesdecimales continet quaesita distantia BR.DEMONST. Angulus dAO=BRS,& dOA=BSR (15) ergo in triangu-lis Ad O & BSR erit Ad: BR=AO:RS (216 sicut ergo ex const.RS totperticas &c., quot AO partes decimas&c. continet, ità BR tot continebitperticas &c., quot partes scalae decimas&c. continet Ad. q. e. d.241. SOLUTIO. II. Per astrolabium.I. Metire angulos BRS, & BSR (98)& intervallum Rs. II. In charta duc re-ctam AQ, quae in partibus scalae exhi-beat