lg tg 33' = 9.34244733' = + 12° 24' 29". 1i (X' + X) = — 64 25 21 .0

/<7 33" = 0.645696,,33" = — 77° 15' 34".4l (X" + X) = — 102 57 25 .2

g' = — 76°49' 50". 1$ (<£' - ®) = + 25 33 59 .7

.vm l (X' — X) = 9.090907lg cotg l ß> — 8) = 0.285531comp //7 .vir« 33' = 0.667817

<£" = — 25°41'50".8$(<£" + £)=_ 51 15 50 .5

lg sin l (X" - X) = 9.717501,,lg cotg \ ß" — 8) — 0.661241comp lg sin 33" = 0.010827,,

l (X' - X) =.+ 7" 4' 54".0l <ß' - 6) = +27 23 30 .2| (<?' - 8) = +47 27 30 .7

lg tg l (X' — X) = 9.094232lg cotg 3 (<?' — 6 = 0.285531lg cotg \ (ß> + 8) — 9.962684

|(X" —X) = — 31 "27' 10",21 ß" - d) = — 12 18 23 .0\ iß" + d) = + 32 22 23 .5

lg tg l (X" — X) = 9.786517,,lg cotg l ß" — 8) = 0.661241lg cotg l ß" + 8) = 0.197938

lg 31' = 0.044255lg 31" = 0.389569

lg lg % — 9.654686% = 24° 18' 2".045°- « = 20 41 58 .0

tg (j = cotg <f cos (X + x)

sinh = sin(S ' sin ^ + <?)

COS tj

lg 3t" = 0.389569

&" = — 25° 41' 50".8x = + 89 34 0 .7

S" + o; = + 63° 52' 9".9lg cos (£" + x) =9.643865lg 31" = 0.389569

lg tg <7. = 0.033434y> = Polhöhe = 47° 12' 11".8

384

muss, die Uhrangabe T = 1 V 1 0' 0" nehmen; und da die Uhrin jeder Stunde um 9". 19, und in jeder Minute um 0".152gegen Sternzeit zurückblieb, so hat man:

für a Bootis

0= 9/t 22' 12".7

ft(0 — V) — 15 .0

jilt = 14 T 58 .7

0+* (0— T)~ JR = — 4A46' 1".0X=:—7I°30' 15

für ß Urs. min.IIA 1' 57".4+ 0 .314/, 51' 19".5

— 3A49' 21".8

für a Cygni11A37' 58".45 .8

20 35 42 .6

8/157' 38".4

X'= —57°20' 27 "IX"= — 134°24' 35"